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- We'll set each linear Factor equal to 0 so x - 3 = 0 x +
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... that point on our graph already that's the point 0 comma 3 we found that our slope was -4 we could consider that as -4 over Ch4 #1 ChapterTestPrepVideos Sullivan Trig 9e ... goes through the point one comma one and also through the point negative Ch1 #4 ChapterTestPrepVideos Sullivan AT 9e
... some number that's not equal to four For instance we could let a equal one If we let a equal
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