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... by using the distance formula we'd like to find the distance from the point13 to the point 5 - ... so minus 5 to 5 that's the interval we're considering we're going to let X scale be ... so we're going to use parentheses to indicate those values on our number line we'll put

For this problem we're going to examine a piece-wise defined function here we need to consider the function g ofx equals 2x +

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  • ... which is -9 the corresponding point is 09 let x = 2 y = 2^2 - 9 again we get 4 - 99 which is5 2 comma 5 we'll do
  • ... Theta is going to be sin inverse of 10.5 / 12 and we'll get that Theta is approximately
  • ... the right side we'll distribute so we'll have 100 + 5x going to group the variable terms on
  • 5 threes will cancel so we'll have two divid 2 + 5x overx - 5 we get a common denominator multip think of this as 5 over
  • The set of X values such that X is less than or equal to 45ths now we want to evaluate the function the value xal -

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